Respuesta :
Answer:
Approximately 23[tex]\%[/tex] percent of the executives have an income of $925 or less
Step-by-step explanation:
Given -
Mean income [tex]\boldsymbol{(\nu)}[/tex] = $1,000
Standard deviation [tex]\boldsymbol{(\sigma )}[/tex] = $100
Let X be the income of group of executives
what percent of the executives have an income of $925 or less =
[tex]P(X\leq 925 )[/tex] = [tex]P(\frac{X - \nu }{\sigma}\leq \frac{925 - 1000)}{100}[/tex])
= [tex]P(Z\leq \frac{-75}{100} )[/tex] Put [ [tex]\boldsymbol{Z = \frac{X - \nu }{\sigma}}[/tex] ]
= [tex]P(Z\leq -0.75)[/tex] Using Z table
= .2266
= [tex]22.66\%[/tex]
= [tex]23%[/tex][tex]\%[/tex] (Approximately)
