the total area of sections 1 and 2 is 48 Â square units !
Step-by-step explanation:
Here we have , Â The triangle and the rectangle have the same base, b, and height, h. Â If the area of the triangle is 48 square units,We need to find what is the total area of sections 1 and 2 . Let's find out:
According to question , we have a triangle with same base and height as of rectangle inside a rectangle ! Following are the parameters of rectangle:
[tex]Length= b\\width= h\\[/tex]
but , Area of rectangle = [tex]length(width)[/tex] . Also , Area of triangle :
⇒ [tex]\frac{1}{2} (b)(h) = 48[/tex]
⇒ [tex](b)(h) = 96[/tex]
So , Area of rectangle = Â [tex](b)(h) = 96[/tex] . Total area of section 1 & 2 is given by :
⇒ [tex]96=48+Area[/tex]
⇒ [tex]Area=48[/tex]
Therefore , the total area of sections 1 and 2 is 48 square units !
