Answer: -6.67 m/s²
Explanation:
Given that,
Initial velocity of car (Vi) = 60 m/s
Final velocity of car (Vf) = 20 m/s
Time taken (T) = 6 seconds
Deceleration (A) = ?
Deceleration is the rate of change of velocity per unit time as the car prepares to rest (slows down)
i.e Deceleration = (Vf - Vi)/T
A = (20 m/s - 60km/s) / 6 seconds
A = -40 m/s / 6 seconds
A = -6.67 m/s² (The negative sign indicates that the car is slowing down)
Thus, the deceleration of the car is -6.67m/s²
