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14-04-2020
Mathematics

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Evaluate the expression P(9,3), equivalently 9P3
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jimrgrant1 jimrgrant1

14-04-2020

Answer:

504

Step-by-step explanation:

Using the definition

n[tex]P_{r}[/tex] = [tex]\frac{n!}{(n-r)!}[/tex]

where n! = n(n - 1)(n - 2).... × 3 × 2 × 1

Thus

9[tex]P_{3}[/tex] = [tex]\frac{9!}{6!}[/tex] ← cancel the terms of 6! on numerator/denominator, leaving

= 9 × 8 × 7 = 504

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