Answer:
C) 20 m/s
Explanation:
The collision of the car and truck will give a single resultant velocity due to equal masses.
We'll treat this question as a vector question.
The velocity profile will form a right angle triangle.
To calculate the velocity of the car
Let the velocity be x
Sina = x/28
Sin46= x/28
0.7193*28 = x
20 = x
X = 20 m/s
Resolving horizontally, the car is initially traveling at the speed of 40 m/s approximately. The correct answer is option D
Given that a car heading north collides at an intersection with a truck heading east. if they lock together and travel 28 m/s at 46 degrees north of east just after the collision, it is assumed that the two vehicles have the same mass.
The degree to the horizontal will be 90 - 46 = 44 degrees
And since we are focusing on how fast was the car initially traveling, let us resolve the momentum after collision horizontally. That is,
Momentum before collision = momentum after collision
mU + 0 = (m + m) x 28 cos 44
Note: horizontally, momentum of the truck = 0
mU = 2m x 20.14
The mass m will cancel out.
U = 40.28 m/s
Therefore, the car is initially traveling at the speed of 40 m/s approximately. The correct answer is option D
Learn more about momentum here: https://brainly.com/question/25849204
