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The average intensity of light emerging from a polarizing sheet is 0.764 W/m^2, and the average intensity of the horizontally polarized light incident on the sheet is 0.883 W/m^2. Determine the angle that the transmission axis of the polarizing sheet makes with the horizontal.

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onyebuchinnaji

Answer:

The angle that the transmission axis of the polarizing sheet makes with the horizontal is 21.55ā°

Explanation:

Given;

average intensity of incident light, I = 0.764 W/mĀ²

average intensity of transmitted light, Iā‚€ = 0.883 W/mĀ²

I = Iā‚€CosĀ²Īø

where;

Īø is the angle that the transmission axis of the polarizing sheet makes with the horizontal.

CosĀ²Īø = I / Iā‚€

CosĀ²Īø = 0.764/0.883

CosĀ²Īø = 0.8652

CosĪø = āˆš0.8652

CosĪø = 0.9301

Īø = Cosā»Ā¹ 0.9301

Īø = 21.55ā°

Therefore, the angle that the transmission axis of the polarizing sheet makes with the horizontal is 21.55ā°

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