Assume a satellite shines an unpolarized light on a telescope. The intensity of the light as it reaches the telescope is 1.1*10-10 W/m2 a lit, 1000-watt light bulb mounted on it. The unpolarized light from the light bulb, upon reaching the telescope, is passed through two polarizing filters that are at an angle of 30° with respect to each other, and then the resulting light is projected onto a CCD camera. What is the intensity of the light detected by the camera?

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boffeemadrid boffeemadrid · Answer 1 · 2020-04-17T07:57:40+02:00

Answer:

[tex]4.125\times 10^{-11}\ W/m^2[/tex]

Explanation:

[tex]I_0[/tex] = Intensity of unpolarized light = [tex]1.1\times 10^{-10}\ W/m^2[/tex]

[tex]\theta[/tex] = Angle of the filter = [tex]30^{\circ}[/tex]

Intensity of light is given by

[tex]I=\dfrac{I_0}{2}cos^2\theta\\\Rightarrow I=\dfrac{1.1\times 10^{-10}}{2}cos^230\\\Rightarrow I=4.125\times 10^{-11}\ W/m^2[/tex]

The intensity of light detected by the camera is [tex]4.125\times 10^{-11}\ W/m^2[/tex]