Answer:
The altitude is 5.03 m
Explanation:
Given:
Mass of pole [tex]m = 52[/tex] kg
Speed of vaulter [tex]v_{i} = 10\frac{m}{s}[/tex]
Speed of vaulter when she is above the bar [tex]v_{f} = 1.2 \frac{m}{s}[/tex]
For finding altitude we use conservation of energy,
[tex]\Delta E _{i} = \Delta E _{f}[/tex]
[tex]\frac{1}{2} m v_{f} ^{2} + mgh= \frac{1}{2} m v _{i} ^{2} +0[/tex] ( ∵ initial height is zero )
[tex]v_{i} ^{2} - v_{f} ^{2} = 2g h[/tex]
[tex]h = \frac{v_{i} ^{2} - v_{f} ^{2}}{2g}[/tex]
[tex]h = \frac{100-1.44}{2 \times 9.8}[/tex] ( ∵ [tex]g = 9.8 \frac{m}{s^{2} }[/tex] )
[tex]h = 5.03[/tex] m
Therefore, the altitude is 5.03 m
