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two unknown Pea plants are crossed. 75% for 3/4 of the plants have axial flowers and 25% or 1/4 have terminal flowers. what are the genotypes of the parents ?

Respuesta :

Answer:

Aa x Aa

Explanation:

Using axial is dominant (A) and terminal is recessive (a). For a recessive trait to show up at all, both parents must have at least one recessive character.

You can solve this using a punnett square

Aa x Aa -> (1) AA (2) Aa (1) aa

This gives a 3:1 ratio or 75%/25% ratio of axial to terminal flowers

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