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A tiny but horrible alien is standing at the top of the Empire State Building (which is
443
443443 meters tall) and threatening to destroy the city of New York!
A Men In Black agent is standing at ground level,
18
1818 meters across the street, aiming his laser gun at the alien.
At what angle, in degrees, should the agent shoot his laser gun?
Round your final answer to the nearest tenth.
Please help

Respuesta :

Answer:

87.7 degrees.

Step-by-step explanation:

In triangle ABC, attached.

The height of the building |AB|=443 meters

The distance of the agent across the street , |BC|=18 meters

We want to determine the angle at C.

Now,

[tex]Tan C=\dfrac{|AB|}{|BC|} \\C=arctan (\dfrac{|AB|}{|BC|} )\\=arctan (\dfrac{443}{18} )\\=87.67^\circ\\\approx 87.7^\circ $(correct to the nearest tenth)[/tex]

The agent should sfoot his laser gun at an angle of 87.7 degrees.

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