Respuesta :
Answer: The heat of reaction for the combustion of titanium is 15240 kJ/mol
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
[tex]Q=C\times \Delta T[/tex]
Q = Heat absorbed by calorimeter =?
C = heat capacity of calorimeter = 9.84 kJ/K
Initial temperature of the calorimeter = [tex]T_i[/tex] = [tex]25.00^0C=(25.00+273)=298.00K[/tex]
Final temperature of the calorimeter = [tex]T_f[/tex] = [tex]91.60^0C=(91.60+273)K=364.6K[/tex]
Change in temperature ,[tex]\Delta T=T_f-T_i=(364.6-298.0)K=66.60K[/tex]
Putting in the values, we get:
[tex]Q=9.84kJ/K\times 66.60K=655.3kJ[/tex]
As heat absorbed by calorimeter is equal to heat released by combustion of titanium
[tex]Q=q[/tex]
[tex]\text{Moles of titanium}=\frac{\text{given mass}}{\text{Molar Mass}}=\frac{2.060g}{47.8g/mol}=0.0430mol[/tex]
Heat released by 0.0430 moles of titanium = 655.3 kJ
Heat released by 1 mole of titanium = [tex]\frac{655.3}{0.0430}\times 1=15240kJ[/tex]
The heat of reaction for the combustion of titanium is 15240 kJ/mol
