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50 POINTS PLS HELP!!!
FUNDAMENTAL PRINCIPLE OF COUNTING
1. Choose any two digits. How many different ways can those digits be arranged?
2. Choose any three letters of the alphabet. How many different ways can those letters be arranged?
3. Suppose you had to complete four chores, and you could complete the chores in any order. In how many different ways could you complete the chores?

Respuesta :

mysticchacha

Answer:

1.) 90 ways

2.) 15,600 ways

3.) 24 ways

Step-by-step explanation:

1.)  Let's say   we are given 2 digits not equal to each other...The number of different orderings would be  2*1 = 2, or  if we wanted the number of ways to order 2 digits chosen :   10*9 = 90 ways

2.)   The number of ways to arrange 3 letters from 26 letters is:

26 Permutes 3  =    26! / (26 -3)!  =  26*25*24 = 15,600 ways to choose 3 letters in a certain order

3.) 4 different chores.  The number of ways to do them =  4*3*2 *1 = 24 ways

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