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Four point charges, each having a magnitude of 2:00 C, are fixed at the corners of a square whose edges are 4:00m long. Find the electric potential at the center of the square if three of the charges are positive and one charge is negative.

Respuesta :

Answer:

Explanation:

Distance of each of the charges from the center are equal . If this distance be d

d = .5 x length of diagonal of square

length of diagonal = 4√2

d = .5 x 4√2

= 2√2

potential at a point

V = k Q / r where k is a constant , Q is charge and r is distance of the point from the charge .

k = 9 x 10⁹

Total potential = [tex]\frac{9\times10^9\times3 \times2}{2\sqrt{2} } -[/tex][tex]\frac{9\times10^9 \times2}{2\sqrt{2} }[/tex]

= [tex]\frac{9\times10^9 \times2\times2}{2\sqrt{2} }[/tex]

= 9 √2 x 10⁹ V .

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