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Calculate the equilibrium constant K for the following reaction: H2(g) +
Cl2(g) = 2 HCI (g) at equilibrium, [HCl] = 0.0625 M, [H2] = 0.0045 M, [CI2]
0.0045 M*

Respuesta :

asuwafohjames

Answer:

192.9

Explanation:

From the question,

Ke = [HCL]²/[H₂][CL₂].......................... Equation 1

Where Ke = Equilibrium constant.

Given: [HCL] = 0.0625 M, [H₂] = 0.0045 M, [CL₂] = 0.0045 M

Substitute these values into equation 1

Ke = (0.0625)²/(0.0045)(0.0045)

ke = (3.90625×10⁻³)/(2.025×10⁻⁵)

ke = 1.929×10²

ke = 192.9

Hence the equilibrium constant of the system = 192.9

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