A local school needs to paint the floor of its theater room, where the length of the floor, x, is at least 12 feet. The width of the floor is 4 feet less than the length. It will have a stage and a closet, and the remaining area of the floor will be painted. The dimensions are shown in the diagram:

Let A represent the painted area, in square feet, of the floor. Choose the correct equation to solve for area (A).

A = x(x − 4) + 0.5(6)(x − 4) + 2(7)
A = x(x − 4) − 0.5(6)(x − 4) − 2(7)
A = x(x − 4) − (6)(x − 4) − 2(7)
A = x(x − 4) + (6)(x − 4) + 2(7)

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Chelboy Chelboy · Answer 1 · 2020-05-10T23:01:27+02:00

Answer:A=x(x-4)-0.5(6)(x-4)-2(7)

Step-by-step explanation:

A=x(x-4)-(0.5(6)(x-4) + 2(7))

A=x(x-4)-0.5(6)(x-4)-2(7)

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ashishdwivedilVT ashishdwivedilVT · Answer 2 · 2022-07-14T16:43:15+02:00

The printed area of the theater room is x(x − 4) − 0.5(6)(x − 4) − 2(7). Then the correct option B.

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

A local school needs to paint the floor of its theater room, where the length of the floor, x, is at least 11 feet.

The width of the floor is 4 feet less than the length.

It will have a stage and a closet, and the remaining area of the floor will be painted.

Let, the length be x ft

Then the width will be (x - 4) ft

Then the stage closest will be

6(x-4)/2 = 3(x-4)

The rectangle is 7(2)

The painted area will be given as

x(x-4) - 4(x-4)

Then we have

Area = x(x-4) - 0.5(6)(x-4) - 2(7)

Thus, The printed area of the theater room is x(x − 4) − 0.5(6)(x − 4) − 2(7). Then the correct option B.

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