Answer:
The current is  [tex]I = 0.4595 \ A[/tex]
Explanation:
From the question we are told that
  The length of the wire is  [tex]L = 64.7 \ cm = 0.647 \ m[/tex]
  The magnetic field is  [tex]B = 0.370 \ T[/tex]
   The magnetic force is  [tex]F = 0.110 \ N[/tex]
Generally the magnetic force exerted by the field is mathematically represented as
   [tex]F = IL B sin \theta[/tex]
Making I the subject we have
   [tex]I = \frac{F}{LB \ sin\theta}[/tex]
The angle here is  90° since the wire is perpendicular  to the direction of the magnetic field
   Substituting values
   [tex]I = \frac{0.110}{ (0.370) * 0.647 \ sin(90)}[/tex]
  [tex]I = 0.4595 \ A[/tex]
