aliimran20210
contestada

plz help i need the answer ASAP If 6.20 cm3 of a 6.75 M (M = mol/dm3) solution are diluted to 85.6 cm3 with water, what is the concentration of the final solution?

A. 6.75 (6.20/85.6)

B. 6.75 (8.56/6.20)

C. 6.75 (6200/85.6)

D. 6.75 (85.6/6200)

a) A
b) B
c) C
d) D

Respuesta :

Eduard22sly

Answer:

Option A. 6.75 (6.20/85.6)

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 6.2cm³

Initial concentration (C1) = 6.75M

Final volume (V2) = 85.6cm³

Final concentration (C2) =.?

The final concentration can be obtained by using the dilution formula as show below:

C1V1 = C2V2

6.75 x 6.2 = C2 x 85.6

Divide both side by 85.6

C2 = (6.75 x 6.2) /85.6

C2 = 6.75 (6.2 / 85.6).