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Write a Lewis structure for each atom or ion. Draw the particle by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons and non-bonding electrons. Show the charge of the atom. Particles: S2-, Mg, Mg+2, P.

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Answer:

The Lewis structure to this question can be described as follows:

Explanation:

Structure of Lewis for  [tex]S^{2-}[/tex]:  

The maximum number of electrons from valence in [tex]S^{2-}[/tex]  is 8 (6 from S as well as 2 from negative change).  

The valence electrons in the Lewis structure are placed on four sides of the atom.  

Thus the structure of Lewis for [tex]S^{2-}[/tex] is as follows:

[tex]\left[\begin{array}{ccc} &. .&\\: &S&:\\&. .&\end{array}\right] ^{2-}[/tex]

Lewis Mg Structure:  

Complete valence electrons are 2 in Mg.  

The Lewis structure for Mg, therefore, is as follows:

[tex]\ . \\ Mg\\ \ .[/tex]

The Lewis structure for  [tex]Mg^{2+}[/tex]

The maximum valence of electrons   [tex]Mg^{2+}[/tex] in is=  0.

Thus, the structure for   [tex]Mg^{2+}[/tex] is as follows:

 [tex]Mg^{2+}[/tex]

Lewis structure for P :

The maximum number of valence electrons in P is = 5.

Thus, the structure for P is=

[tex]\ \ \ . \\ : P \ : \\[/tex]

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