Answer:
$204
Step-by-step explanation:
The question is at what price x will the company maximize revenue.
The revenue function is:
[tex]R(x) = 4,080x-10x^2[/tex]
The price for which the derivate of the revenue function is zero is the price the maximizes revenue:
[tex]R(x) = 4,080x-10x^2\\\frac{dR(x)}{dx}=0=4,080-20x\\x=\frac{4,080}{20}\\ x=\$204[/tex]
The company will maximize its revenue when the price is $204.
