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A 10.0 L balloon contains helium gas at a pressure of 655 mmHg. What is the new pressure, in mm Hg, of the helium gas if the volume is 20.0 L and if there is no change in temperature or quantity? 6550 mmHg 1000 mm Hg 1310 mmHg 300 mm Hg

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aprilhall

Answer:

327.5 mmHg

Explanation:

By Boyle's law, P1V1=P2V2

10 L * 655 mmHg = 20 L * x

solve for x

x= (10*655)/20

x=327.5 mmHg

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