Answer:
s = 1989.9 m
Explanation:
In order to find the distance at which the engineer should apply brake, we can use 2nd equation of motion. The second equation of motion is as follows:
s = Vi t + (0.5)at²
where,
s = distance from the station = ?
Vi = Initial velocity = 44 m/s
t = time required to stop = 27 s
a = acceleration of train = 2.2 m/s²
Therefore,
s = (44 m/s)(27 s) + (0.5)(2.2 m/s²)(27 s)²
s = 1188 m + 801.9 m
s = 1989.9 m
