Respuesta :

Let d = 0.825252525..., then
[tex]10d = 8.25252525...=8\frac{25}{10^2-1}=8\frac{25}{99}[/tex]

Therefore,
[tex]d=\frac{8}{10}+\frac{25}{990}=\frac{8(99)+25}{990}=\frac{817}{990}[/tex]