Answer:
The correct answer is - 1.57 × 10⁶ codons.
Explanation:
Given:
No. of base pairs in E.coli DNA = 4.70 × 10⁶
we know :
1 codon = 3 DNA nucleotides
Solution:
No. of of base pairs in DNA = No. of nucleotides in a single strand
= 4.70 × 10⁶
It must have 1/3 this number of triplet codons
= 4.70 × 10⁶ / 3
= 1.57 × 10⁶ codons.
Thus, the correct answer is - 1.57 × 10⁶ codons.
