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A resistive element of 50-ohm resistance is connected through a voltage source with the equation v(t) = 100 sin (100t – 10°) V. At what time will the amount of current be at +1 A for the first time?

Respuesta :

hamzaahmeds

Answer:

t = 0.4 s

Explanation:

Here, we will use Ohm's Law to find out the value of time at which the current in resistive element becomes 1 A. Therefore,

V = IR

V(t)/R = I

where,

V(t) = Voltage in terms of time = 100 Sin (100t - 10)

R = Resistance of the element = 50 Ω

I = Current = 1 A

Therefore,

100 Sin (100t - 10)/50 Ω = 1 A

Sin (100t - 10) = 1/2

100t - 10 = Sin⁻¹(1/2)

100t = 10 + 30

t = 40/100

t = 0.4 s