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A ball is dropped from an upper floor, some unknown distance above Tom's apartment. As he looks out of his window, which is 1.10 m tall, Tom observes that it takes the ball 0.190 s to traverse the length of the window. Determine how high ℎ above the top of Tom's window the ball was dropped. Ignore the effects of air resistance.

Respuesta :

Answer:

The height is 1.20 m above the window.

Explanation:

Given that,

Height of window = 1.10 m

Time = 0.190 sec

We need to calculate the velocity

Using equation of motion

[tex]s=ut+\dfrac{1}{2}gt^2[/tex]

Put the value into the formula

[tex]1.10=u\times0.190+\dfrac{1}{2}\times9.8\times(0.190)^2[/tex]

[tex]1.10=u\times0.190+0.17689[/tex]

[tex]u=\dfrac{1.10-0.17689}{0.190}[/tex]

[tex]u=4.85\ m/s[/tex]

We need to calculate the height

Using equation of motion

[tex]v^2=u^2+2gh[/tex]

Put the value into the formula

[tex](4.85)^2=0+2\times9.8\times h[/tex]

[tex]h=\dfrac{(4.85)^2}{2\times9.8}[/tex]

[tex]h=1.20\ m[/tex]

Hence, The height is 1.20 m above the window.