Answer:
see explanation
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
Here m = [tex]\frac{1}{2}[/tex] and (a, b) = (3, - 2) , thus
y - (- 2) = [tex]\frac{1}{2}[/tex] (x - 3) , that is
y + 2 = [tex]\frac{1}{2}[/tex]( x - 3) ← in point- slope form
(b)
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = [tex]\frac{1}{2}[/tex] , thus
y = [tex]\frac{1}{2}[/tex] x + c ← is the partial equation
To find c substitute (3, - 2) into the partial equation
- 2 = [tex]\frac{3}{2}[/tex] + c ⇒ c = - 2 - [tex]\frac{3}{2}[/tex] = - [tex]\frac{7}{2}[/tex]
y = [tex]\frac{1}{2}[/tex] x - [tex]\frac{7}{2}[/tex] ← in slope- intercept form
