HELP ASAP!!!!!!!! Select the correct answer from each drop-down menu.
The graph of the function y= x^2(x^2 - 6x + 9) has zeros of (0 and -3, -3 and 3, 0 and 3, -3 and 3)
complex zeros.
so the function has (no, two, three, four)
distinct real zeros and (no, two, three, four) complex zeros.

Respuesta :

Answer: The answer is

1. 0 and 3

2. Two

3. No

Step-by-step explanation:

I took the test and it's right

The graph of the function has zeros of 0 and 3, two distinct real zeros, and no complex zeros.

What is a function?

It is defined as a special type of relationship and they have a predefined domain and range according to the function.

We have a function:

[tex]\rm y= x^2(x^2 - 6x + 9)[/tex]

We can write it as a:

[tex]\rm y= x^2(x^2 - 2(3)(x)+ 3^2)[/tex]

[tex]\rm y = x^2(x-3)^2[/tex]

To find the zeros equate to the function with the zero.

y = 0

[tex]\rm x^2(x-3)^2=0[/tex]

First, take [tex]\rm x^2= 0[/tex] we get:

x = 0

Now

[tex]\rm (x-3)^2=0[/tex]

x - 3 = 0

x = 3

Thus, the graph of the function has zeros of 0 and 3, two distinct real zeros, and no complex zeros.

Learn more about the function here:

brainly.com/question/5245372