1. A Mars rover is packed inside an airbag lander that will bounce on the surface of the planet. The rover will bounce many times before coming to a stop. It is projected that on the first bounce, the lander will project upward at 75° above the horizon with a speed of 9.92m/s. A. How much time will elapse between this first bounce and the second bounce

Respuesta :

Answer:

The value is [tex]t = 5.15 \ seconds [/tex]

Explanation:

From the question we are told that

   The  angle is  [tex]\theta  =  75^o[/tex]

   The speed is  [tex]v  =  9.92 \  m/s[/tex]

   

The  time taken is mathematically represented as

     [tex]t =  \frac{ 2 * v * sin (\theta )}{ g}[/tex]

=>    [tex]t =  \frac{ 2 *9.92 * sin (75 )}{ 9.8}[/tex]

=>    [tex]t = 5.15 \ seconds [/tex]