If I haven't already convinced you that your teacher is nothing but a purveyor of falsity, check this out. Let β†’ u be a vector such that | β†’ u | = 1 . Choose a vector β†’ v such that β†’ u β‹… β†’ v = = 3 and | β†’ v | = √ 5 . Now we have, | β†’ u βˆ’ β†’ v | = ( β†’ u βˆ’ β†’ v ) β‹… ( β†’ u βˆ’ β†’ v ) = β†’ u β‹… β†’ u βˆ’ 2 ( β†’ u β‹… β†’ v ) + β†’ v β‹… β†’ v = 0 Hence, β†’ u = β†’ v , since β†’ u βˆ’ β†’ v = 0 . But β†’ u and β†’ v have different lengths!! Well, gosh darn him anyway! Question #2: How can two things be the same and yet different? Explain.