contestada

(A) Hemoglobin is 50% saturated (P50) at 20 torr, which is approximately equal to the partial pressure of O2 in muscle. The partial pressure of O2 in the lungs is 100 torr. If the Hill coefficient nh = 3, calculate how efficient hemoglobin is at O2 delivery. Express your answer as the difference between factional O2 binding in the lungs and fractional O2 binding in muscle (qlungs – qmuscle). (B) How would the efficiency of O2 delivery change if hemoglobin were not cooperative (i.e. if nh =1)?

Respuesta :

ajeigbeibraheem

Answer:

Explanation:

Given that:

Pâ‚…â‚€ = 20 torr in muscle

The partial pressure of O2 in lungs Poâ‚‚ = 100 torr

The hill coefficient [tex]n_h[/tex] = 3

According to the Hill coefficient;

[tex]\dfrac{\Upsilon}{1-\Upsilon}= (\dfrac{PO_2}{P_{50}})^n[/tex]

here;

[tex]\Upsilon[/tex] = fraction of haemoglobin monomers

[tex]\dfrac{\Upsilon}{1-\Upsilon}= (\dfrac{100}{20})^3[/tex]

[tex]\dfrac{\Upsilon}{1-\Upsilon}[/tex] = 125 θ lungs

However for θ muscle :

[tex](\dfrac{PO_2}{P_{50}})^n=( \dfrac{20}{20})^3[/tex]

= 125 (θ lungs) - 1 (θ muscle)

= 124

B.

if nh =1

[tex]\mathtt {\theta \ lungs} = \dfrac{\Upsilon}{1-\Upsilon}= (\dfrac{100}{20})^1[/tex]

[tex]\mathtt {\theta \ lungs} =5[/tex]

[tex]\mathtt {\theta \ muscle} = \dfrac{20}{20}^1[/tex]

(θ muscle) = 1

(θ lungs) - (θ muscle) = 5 - 1

(θ lungs) - (θ muscle) = 4

batolisis

A) The efficiency of hemoglobin at Oâ‚‚ delivery = 124

B) Efficiency of O₂ delivery will change by : 4  

Given data:

Partial pressure of O₂ in lungs ( PO₂ )  = 100 torr

Partial pressure of O₂ in muscle  = ( P₅₀ ) = 20 torr

Hill coefficient nh = 3

r = fraction of hemoglobin monomers

A) Determine the efficiency of hemoglobin at Oâ‚‚ delivery

Given that Hill coefficient = [tex]\frac{r}{1-r} = (\frac{PO_{2} }{P_{50} } )^{n}[/tex]  

                                          = [tex]\frac{r}{1-r} = (\frac{100}{20})^{3}[/tex]  = 125 ∅ Lungs

For Muscle :

[tex](\frac{20}{20} )^{3}[/tex] =  1 ∅ muscle

Therefore the efficiency of hemoglobin at 0â‚‚ delivery

= ( ∅ lungs - ∅ muscle )

=  ( 125 - 1 )  = 124

B )  Determine the change in efficiency of O2 delivery

when hill coefficient ( nh ) = 1

for lungs :

[tex]\frac{r}{1-r} = (\frac{100}{20})^{1}[/tex]  = 5

for muscle :

[tex](\frac{20}{20} )^{1}[/tex]   = 1

Therefore change on efficiency =  ( 5 - 1 ) = 4

Hence we can conclude that The efficiency of hemoglobin at O₂ delivery = 124 and Efficiency of O₂ delivery will change by  4  

Learn more : https://brainly.com/question/13531301

Otras preguntas