The resulting temperature : 546.91 K = 273.91 Ā°C
Boyle's law and Gay Lussac's law Ā
[tex]\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}[/tex]
P1 = initial gas pressure (N/mĀ² or Pa) Ā
V1 = initial gas volume (mĀ³) Ā
P2 = final gas pressure Ā
V2 = the final volume of gas Ā
T1 = initial gas temperature (K) Ā
T2 = final gas temperature Ā
Pā=10 atm
Vā=2.36 L
Tā=25+273=298 K
Pā=5.56 atm
Vā=7.79 L
[tex]\tt T_2=\dfrac{P_2.V_2.T_1}{P_1.V_1}\\\\T_2=\dfrac{5.56.\times 7.79\times 298}{10\times 2.36}\\\\T_2=546.91~K=273.91^oC[/tex]
