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A mixture of nitrogen and xenon gases contains nitrogen at a partial pressure of 417 mm Hg and xenon at a partial pressure of 427 mm Hg. What is the mole fraction of each gas in the mixture

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boffeemadrid

Answer:

0.4941, 0.5059

Explanation:

[tex]P_N[/tex] = Partial pressure of nitrogen = 417 mm Hg

[tex]P_{Xe}[/tex] = Partial pressure of xenon = 427 mm Hg

Total pressure in the system is given by

[tex]P=P_N+P_{Xe}\\\Rightarrow P=417+427=844\ \text{mm Hg}[/tex]

Mole fraction is given by

[tex]X_N=\dfrac{P_N}{P}\\\Rightarrow X_N=\dfrac{417}{844}\\\Rightarrow X_{N}=0.4941[/tex]

For xenon

[tex]X_{Xe}=1-0.4941=0.5059[/tex]

or

[tex]X_{Xe}=\dfrac{P_{Xe}}{P}\\\Rightarrow X_{Xe}=\dfrac{427}{844}\\\Rightarrow X_{Xe}=0.5059[/tex]

So, mole fraction of nitrogen is 0.4941 and xenon is 0.5059.

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