contestada

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the
time after launch, x in seconds, by the given equation. Using this equation, find the
time that the rocket will hit the ground, to the nearest 100th of second.
y = -16x2 + 247x + 141

Respuesta :

Answer: 15,99s

when the rocket hit the ground => y = 0

=> -16xΒ² + 247x + 141 = 0 (*)

a = - 16 Β  Β  Β b = 247 Β  Β  c = 141

Ξ” = bΒ² - 4ac = 247Β² + 16.4.141 = 70033 > 0 => (*) has 2 solutions

=> x = [tex]\frac{247-\sqrt{70033} }{32}=-0,55(removed)[/tex]

or x = [tex]\frac{247+\sqrt{70033} }{32}=15,99(s)[/tex]

Step-by-step explanation:

Otras preguntas