Answer:
151200
Step-by-step explanation:
We want to know how many permutations of 6 digits can be chosen from 10 different digits, so we use the formula:
nPr=n!(nβr)!
Here, r=6 and n=10, so we have:
10P6=10!(10β6)!=10!4!=10β 9β 8β 7β 6β 5β 4!4!=151,200