Answer:
2048 blocks
Explanation:
From the information given:
The memory size of a computer with fully associative cache = 2¹⁶ bytes
The no. of blocks in a single cache = 64
In which each block size = 32 bytes
The no of blocks in the main memory = memory size ÷ block size
The no of blocks in the main memory = 2¹⁶ ÷ 32
The no of blocks in the main memory = 2¹⁶ ÷ 2⁵
The no of blocks in the main memory = [tex]2^{16-5}[/tex]
The no of blocks in the main memory = 2¹¹
The no of blocks in the main memory = 2048 blocks
