Answer:
[tex]d_{i}=465 cm=4.65 m[/tex]
Explanation:
Using the thin lens equation, we have:
[tex]\frac{1}{f}=\frac{1}{d_{o}}+\frac{1}{d_{i}}[/tex]
Where:
f is the focal length
d(o) is the distance of the object
d(i) is the distance of the image
[tex]\frac{1}{15}=\frac{1}{15.5}+\frac{1}{d_{i}}[/tex]
[tex]\frac{1}{15}-\frac{1}{15.5}=\frac{1}{d_{i}}[/tex]
[tex]d_{i}=465 cm=4.65 m[/tex]
Therefore, the screen is at 465 cm.
I hope it helps you!
