Mass of water required = 64.42 g
Given
Reaction
6CO2 + 6H2O → C6H12O6 + 6O2
157.35 g CO2
Required
mass of water
Solution
mol COâ‚‚ = mass : MW COâ‚‚
mol COâ‚‚ = 157.35 g : 44.01 g/mol
mol COâ‚‚ = 3.575
From the equation, mol ratio COâ‚‚ : Hâ‚‚O = 6 : 6, so mol Hâ‚‚O = mol COâ‚‚=3.575
Mass Hâ‚‚O = mol x MW Hâ‚‚O
mass Hâ‚‚O = 3.575 x 18.02
mass Hâ‚‚O = 64.42 g