Answer:
13 is your answer.
let two no. be x and y
by question
x+y=5
x=5-y...........(1)
xy=6.............(2)
putting the value of x in equation 2) we get
(5-y)y=6
5y-y²=6
y²-5y+6=0
y²-3y-2y+6=0
y(y-3)-2(y-3)=0
(y-3)(y-2)=0
either
y=3
or
y=2
putting the value of y in equation 1
when y=3
x=5-3=2
when
y=2
x=5-2=3
now
when
x=3 y=2
the sum of the square of the numbers=x²+y²=3²+2²=9+4=13
