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How many grams of CO are needed to react with an excess of Fe2O3 to produce 209.7 g Fe? Equation Fe2O2(g) + 3CO(g) -> 3CO2(g) + 2Fe(g)

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ihlester

Answer: 157.3 g CO

Explanation:

Fe2O3  + 3CO —> 3CO2 + 2Fe [1 mol + 3 mol —> 3 mol + 2 mol]

3 mol CO —> 2 mol Fe

3*28g —> 2*56g

amt CO 3*28*209.7/(2*56) = 157.3g

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