Answer:
4
Step-by-step explanation:
Given the function
f(x) = 4(4x + 3)(x + 1)² (x^2– 3)
The x-intercept occurs at a point where f(x) = 0
f(x) = 4(4x + 3)(x + 1)² (x^2– 3)
4(4x + 3)(x + 1)² (x^2– 3) = 0
4x+3 = 0
4x = -3
x = -3/4
(x + 1)² = 0
x + 1 = 0
x = 0-1
x = -1
x^2-3 = 0
x^2 = 0+3
x^2 = 3
x = ±√3
hence the x intercepts are -3/4, -1, √3 and -√3. This shows that there are 4 x intercepts
