By how much does the pressure of a gas in a rigid vessel decrease when the temperature drops from 0 ∘C to –1∘C?

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AL2006
If the volume of the container doesn't change, then the pressure of
the gas inside is proportional to its absolute temperature.  That's
the temperature on the Kelvin scale.

0°C  =  273.16 K

-1°C =  272.16 K .

So the gas pressure drops to 

                 (272.16 / 273.16)  = 99.63%

of what it was initially, a precipitous plunge of  0.366 percent.