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Burning one gallon of gasoline in a car releases approximately 20 pounds of CO2 into the atmosphere. One average person drives 60,000 miles in a car that average 30 miles per gallon (mpg), while another person drives 60,000 miles in a car that averages 20 mpg. Over the course of the 60,000 miles, how many fewer punds of CO2 are released by the 30 mpg car than by the 20 mpg car?

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Answer: 20,000 pounds of COâ‚‚

Explanation:

30 mpg car.

Number of gallons of gasoline used:

= 60,000 / 30

= 2,000 gallons

COâ‚‚ released = 2,000 * 20

= 40,000 pounds

20 mpg car

Number of gallons used:

= 60,000 / 20

= 3,000 gallons

COâ‚‚ released = 3,000 * 20

= 60,000 pounds

Difference:

= 60,000 - 40,000

= 20,000 pounds of COâ‚‚

The number of fewer pounds should be 20,000 pounds of COâ‚‚

  • The calculation is as follows:

The Number of gallons of gasoline used:

= 60,000 Ă· 30

= 2,000 gallons

and,

COâ‚‚ released = 2,000 Ă— 20

= 40,000 pounds

Now

Number of gallons used:

= 60,000 ÷  20

= 3,000 gallons

And,

COâ‚‚ released = 3,000 Ă— 20

= 60,000 pounds

So, the Difference is

= 60,000 - 40,000

= 20,000 pounds of COâ‚‚

Learn more: https://brainly.com/question/994316?referrer=searchResults

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