2Na+ 2H20 - > 2NaOH + H2

If 73 g of Na are available, how many moles of NaOH are produced?
PLEASEE HELPPPP

Respuesta :

Answer:

3.17mol

Explanation:

moles of Na = m/M ; Where M - molar mass of Na which is 23

moles of Na = 73/23 =3.17mol

but from the eqn n(Na) : n(NaOH) = 2:2 = 1:1

: . moles of NaOH is also 3.17mol