Answer:
Option a (100 kPa) is the appropriate option.
Explanation:
The given value is:
Original pressure,
P₁ = 50 kPa
Let the new pressure be "x".
Now,
⇒ [tex]\frac{P1}{T_1} =\frac{P_2}{T_2}[/tex]
On substituting the values, we get
⇒ [tex]\frac{50}{T_1} =\frac{x}{2T_1}[/tex]
On applying cross-multiplication, we get
⇒ [tex]x = 50\times 2[/tex]
⇒ [tex]=100 \ kPa[/tex]
Thus the answer above is the right one.
