Respuesta :

(x-2)*(x+2) = x*(x+2) - 2*(x+2)

(x-2)*(x+2) = x*x + x*2 - 2*x - 2*2

(x-2)*(x+2) = x^2 + 2x - 2x - 4

(x-2)*(x+2) = x^2 - 4

That's the long way to do it. You can use the difference of squares formula as a shortcut

(a-b)*(a+b) = a^2 - b^2

(x-2)(x+2) = x^2 - 2^2

(x-2)(x+2) = x^2 - 4

either way, the final answer is x^2 - 4
BobR9
(X-2)(x+2)
So use "f.o.i.l" meaning you multiply each first term, the outside terms, the inside terms and last terms, and then add. You'd get x^2-4 in this example