this may help you
it is given that the standard deviation  0.8, so we can use  the normal distribution critical value for the 95% confidence interval.Â
sample mean = 2.36Â
standard deviation = 0.8Â
standard error of mean = σ / √ nÂ
standard error of mean = 0.8 / √ 50Â
se = 0.8/7.0711Â
standard error of mean 0.1131Â
Confidence interval 2.36-(0.1131)(1.96)Â
and 2.36+(0.1131)(1.96)Â
95% confidence interval :(2.14, 2.58)Â