Respuesta :
This is the question:
4c + 6a ≤ 120
4c + 4a ≤ 100
The answer is Yes, because the bike order meets the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100
Which you can verify by replacing in both equations 10 for c and 12 for a. Look:
1) 4(10) + 6(12) = 40 + 72 = 112 ≤ 120
2) 4(10) + 4(12) = 40 + 48 = 88 ≤ 100
A bicycle manufacturing company makes a particular type of bike.
Each child bike requires 4 hours to build and 4 hours to test.
Each adult bike requires 6 hours to build and 4 hours to test.
With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week.
If c represents child bikes and a represents adult bikes,
determine which system of inequality best explains whether the company can build 10 child bikes and 12 adult bikes in the week
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Now you can state the system of inequalities from the statements
1) First inequality based on the hours availble to buiding
Each child bike requires 4 hours, each adult bike requires 6 hours to build and the company is able to have up to 120 hours of building =>
4c + 6a ≤ 120
2) Second inequality based of the hours available to testing.
Each child bike requires 4 hours to test, each adult bike 4 hours to test and the company is able to have up 100 hours of testing time for a week =>
4c + 4a ≤ 100
Then the two inequalities are:4c + 6a ≤ 120
4c + 4a ≤ 100
The answer is Yes, because the bike order meets the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100
Which you can verify by replacing in both equations 10 for c and 12 for a. Look:
1) 4(10) + 6(12) = 40 + 72 = 112 ≤ 120
2) 4(10) + 4(12) = 40 + 48 = 88 ≤ 100
Answer:
Yes, because the bike order meets the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100
Step-by-step explanation: