Respuesta :
For part A:
9xΒ² - 36x + 36 = 0Β
9(xΒ² - 4x + 4) = 0Β
9(x-2)(x-2) = 0Β
Radicand = Discriminant = 36Β² - 4(9)(36) = 0Β
there is 1 real zero that repeats itself)
zero is x=2.Β
Use factoring. Factors of 7 are 1 and 7Β
2xΒ²-9x+7 = 0
(2x-7)(x-1) = 0Β
2x-7 = 0 Β Β Β Β Β Β Β (x-1)=0Β
2x = 7x=1Β
x = 7/2Β
Your solutions are x = 1 and x = 7/2Β
I hope my answers helped you
9xΒ² - 36x + 36 = 0Β
9(xΒ² - 4x + 4) = 0Β
9(x-2)(x-2) = 0Β
Radicand = Discriminant = 36Β² - 4(9)(36) = 0Β
there is 1 real zero that repeats itself)
zero is x=2.Β
Use factoring. Factors of 7 are 1 and 7Β
2xΒ²-9x+7 = 0
(2x-7)(x-1) = 0Β
2x-7 = 0 Β Β Β Β Β Β Β (x-1)=0Β
2x = 7x=1Β
x = 7/2Β
Your solutions are x = 1 and x = 7/2Β
I hope my answers helped you