A ball rolls with a constant acceleration of 2.5 m/s^2 for 5.0 s with an initial velocity of 5.0 m/s. Calculate the
ball's distance from the starting point at 1.0 s intervals. Make a position-time graph for the object's motion. In
your response, show what you are given, the equation that you used, any algebra/work required, a table of
data, and your graph.

Kinematics studies the motion of bodies, gives relationships between the position, velocity and acceleration of bodies, let's use the relationship

x = v₀ t + ½ a t²

Where x is the position, v or the initial velocity, at the acceleration and t is the time.

Let's substitute

x = 5 t + ½ 2.5 t²

x = 5 t + 1.25 t²

Let's calculate the position and write it in the table

t = 0 s x = 0 m

t = 1 s x = 5 1 + 1.25 1² = 6.25 m

t = 2 s x = 5 2 + 1.25 2² = 15 m

t = 3s x = 5 3 + 1.25 3² = 26.25 m

t = 4 s x = 5 4 + 1.25 4² = 40 m

t = 5 s x = 5 5 + 1.25 5² = 56.25 m

In the following table the time and positions of the body are given, these given are used for the attached graph

time (s) position (m)

0 0

1 6.25

2 15

3 26.25

4 40

5 56.25

In conclusion, using kinematics we can find the answers for the positions of the body as a function of time and make its graph are:

The positions according to time are in the table
In the attachment we can see a graphic representation

Learn more here:

https://brainly.com/question/5063616