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One factor of f(x) = x^3 - 3x^2 - 28x + 60 is (x - 6). What are the zeros of the function? Please show and explain all your steps. Thank you for your help.

Respuesta :

JohnnyG7777

Answer:

Step-by-step explanation:

f(x) = x^3 - 3x^2 - 28x + 60

x(x^2-3x-28)+60

Factor the inside of the parenthesis

Multiples of 28: (1X28),(2X14),(4X7). 7-4=3, 7 & 4 is the correct multiple.

x(x-7)(x+3)+60

Roots: 0,7,-3,6

Also you can plug your function into Desmos and see where it crosses the x-axis.

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